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8h^2-2h=3
We move all terms to the left:
8h^2-2h-(3)=0
a = 8; b = -2; c = -3;
Δ = b2-4ac
Δ = -22-4·8·(-3)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-10}{2*8}=\frac{-8}{16} =-1/2 $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+10}{2*8}=\frac{12}{16} =3/4 $
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